4/3x^2+6=18

Solution for 4/3x^2+6=18 equation:

4/3x^2+6=18

We move all terms to the left:

4/3x^2+6-(18)=0


Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

4/3x^2-12=0

We multiply all the terms by the denominator


-12*3x^2+4=0

Wy multiply elements

-36x^2+4=0

a = -36; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-36)·4
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-36}=\frac{-24}{-72}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-36}=\frac{24}{-72}
=-1/3
$